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Fresnel Model Result

Finally, to obtain the Fresnel model:
  1. Substitute the approximations above.
  2. Apply a time domain Hann window via a frequency domain convolution [1].
This leads to the following expressions for the magnitude and phase of $Y(k)$, valid for $k$ as noted above:
$\displaystyle \angle Y(k)$ $\textstyle \approx$ $\displaystyle \pm \frac{\pi}{4} - \frac{\pi^2 k^2}{K^2\alpha}$ (8)
$\displaystyle \vert Y(k)\vert$ $\textstyle \approx$ $\displaystyle \sqrt{\frac{\pi}{\vert\alpha}\vert}
\left(\ensuremath{\frac{1}{2}...
...math{\frac{1}{2}}\cos\left(\ensuremath{\frac{2\pi^2 k}{KN\alpha}}\right)\right)$ (9)

where the $\ensuremath{\frac{\pi}{4}}$ term in the phase expression is positive for $\alpha>0$ and negative for $\alpha<0$.

As we will see in the next section, these models are invertible.

Aaron S. Master 2003-02-12